Sabine Lisicki of Germany came back to defeat Shahar Peer of Israel 6-3, 4-6, 7-6 (5) on Saturday to advance to the Luxembourg Open final against Timea Bacsinszky of Switzerland. The unseeded Bacsinszky upset fifth-seeded Yanina Wickmayer 3-6, 6-2, 7-5 in the early semifinal, ending the Belgian's eight-match winning streak. Bacsinszky had lost to Wickmayer last week in Linz, Austria, where Wickmayer won her second career WTA Tour title. This time, the Swiss rallied from a set down and held on after blowing a 4-1 lead in the third set. Bacsinszky is playing for her first title in Sunday's final. The sixth-seeded Lisicki fought back from 4-2 down in the third set and 5-3 down in the tiebreaker. Lisicki won her first career title at Charleston in April. She beat Bacsinszky in their only previous match in this year's Fed Cup.
